#definiteintegral
Live, measured metrics for the hashtag #definiteintegral from the open social web. Every number carries a named source and the time it was fetched. Nothing is estimated.
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Day-by-day usage
measured · fosstodon.org (Mastodon public tags API) · fetched 2026-07-27 08:16 UTC0 uses by 0 unique accounts across the window. Real per-day counts, not estimates. Newest bar is today so far.
Related hashtags
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Live pulse
measured · fosstodon.org (Mastodon tag timeline) · fetched 2026-07-27 08:16 UTCEverything below is measured over the latest 6 public posts (spanning ~13613 hours).
Posting hours (UTC)
Languages: English (6)
Avg boosts / post: 0.5
Top of the latest posts
An excellent general result. If \(\Re(s)>1\), \[\displaystyle\int_0^\infty\frac{\ln x}{x^s+1}~\mathrm dx=\frac{\pi^2}{4s^2}\left[\sec^2\left(\frac{\pi}{2s}\right)-\csc^2\left(\frac{\pi}{2s}\right)\right]\] Special cases: \[\displaystyle\int
Take a look at this interesting integral. #MathsChallenge [Hint: use the properties of the Jacobi theta function of the third type \(\vartheta_3(z,q)\)] \[\boxed{\displaystyle\int_0^{\frac{\pi}{4}}\dfrac{1+2\displaystyle\sum_{n\geq1}e^{-n^2
Integral challenge! \[\displaystyle\int_0^\infty\ln\left(1+\dfrac{\cosh\alpha}{\cosh x}\right)\ dx=\dfrac{\pi^2}{8}-\dfrac{\arccos^2(\cosh\alpha)}{2}\] #Integral #Integrals #IntegralChallenge #HyperbolicFunction #HyperbolicCosine #Logarithm
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