#infinitesum
Live, measured metrics for the hashtag #infinitesum from the open social web. Every number carries a named source and the time it was fetched. Nothing is estimated.
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Day-by-day usage
measured · fosstodon.org (Mastodon public tags API) · fetched 2026-07-30 12:47 UTC0 uses by 0 unique accounts across the window. Real per-day counts, not estimates. Newest bar is today so far.
Related hashtags
measured · fosstodon.org (Mastodon public search API) · fetched 2026-07-30 12:47 UTCLive pulse
measured · fosstodon.org (Mastodon tag timeline) · fetched 2026-07-30 12:47 UTCEverything below is measured over the latest 4 public posts (spanning ~17684 hours).
Posting hours (UTC)
Languages: English (4)
Avg boosts / post: 0.8
Top of the latest posts
Let \(\varpi=\dfrac{\Gamma^2\left(\frac14\right)}{2\sqrt{2\pi}}=2.62205755\ldots\) be the lemniscate constant. Then, \[\Large\displaystyle\sum_{n=1}^\infty\dfrac{1}{\sinh^4(\pi n)}=\dfrac{\varpi^4}{30\pi^4}+\dfrac{1}{3\pi}-\dfrac{11}{90}\]
#ThisWeeksFiddler, 20260515 This week the #puzzle is: Can You Play Hide-and-Seek? #minimum #maximum #minmax #coding #probabilities #InfiniteSum #integral I (Nis) am playing hide-and-seek with my nephew. I start at point O, whereas my nephew
Try to prove the following two results that relate the harmonic numbers to the golden ratio. Have an excellent weekend. \[\displaystyle\sum_{n=1}^\infty\binom{2n}n\dfrac{H_n}{5^n}=2\sqrt5\ln\varphi\] \[\displaystyle\sum_{n=1}^\infty\binom{2
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